Kinetic Energy Theorem

Lab Five: lend energising capacity Theorem: W = ? K.E. June 12, 2012 Data Table star: Work energising nada Theorem: W = ? K.E. T1| T2| V1| V2| KE1| KE2| W| 0.230 s| 0.091 s| .435 m/s| 1.11 m/s| .027 J| .240 J| 5.38 J| 0.237 s| 0.091 s| .422 m/s| 1.11 m/s| .026 J| .240 J| 5.39 J| 0.230 s| 0.091 s| .435 m/s| 1.11 m/s | .027 J| .240 J| 5.38 J| Calculations 1. V1 = d / t1 Length of the glider: 10 centimeters 10 centimeters = .1 meters .1 / 0.230 = .435 m/s 2. V2 = d / t2 Length of the glider: 10 centimeters 10 centimeters = .1 meters .1 / 0.091 = 1.11 m/s 3. KE1 = ½ MV2 The mass of the glider on a pan symmetry: 189.3 grams 100 grams added to the glider. Length of the glider: 10 centimeters ½ (100 g + 189.3 g / 1000) (.435)2 ½ (.289300) (.189225) .027371 J .027 J 4. KE2 = ½ MV2 The mass of the glider on a pan suspension: 189.3 grams 200 grams added to the glider. Length of the glider: 10 centimeters ½ (200 g + 189.3 g / 1000) (1.11)2 ½ (.389300) (1.232100) .239828 J .240 J 5. W = ½ M (Vf 2 Vi2 ) ½ (189.

3) (.2402 - .0272) (94.650000)(.056871) 5.382840 J 5.38 J Questions 1. What force does the work? kinetic energy is the force that does the work. 2. What ar the doable sources of error in this experiment Some possible errors in experiment quintuple: students not setting the path of the photogate to gate, not number the air blower for the cut to maximum power, nor remembering the pane to release the glider for all(prenominal) opposite trials (same point for each unlike trials). A car campaign thirty miles per hour, a pile throwing a baseball go miles per hour, an athlete test fifteen miles per hour, all three diverse situations are examples of energising energy. Kinetic energy is defined as the energy of motion, the...If you call for to express a full essay, grade it on our website: Orderessay

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